Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!
Answer: A. True Explanation The Python code initializes two variables, a and b, using string multiplication. a = ("p" * 2) * 3 The inner part ("p" * 2) results in the string "pp". The outer part ("pp" * 3) multiplies this string, resulting in "pppppp". b = ("p" * 3) * 2
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The answer is True because multiplication is the same regardless of order. In maths, it's called Commutativity
a = ("p" * 2) * 3 → "pp" * 3 → "pppppp". b = ("p" * 3) * 2 → "ppp" * 2 → "pppppp". print(a == b) → Compares "pppppp" == "pppppp" → True. Answer: A. True. It's my Day 5th of learning Python 🐍😄 join me along 🫶🏻
Answer: A) True String multiplication + simple math! › a = ("p" * 2) * 3 = "pp" * 3 = "pppppp" › b = ("p" * 3) * 2 = "ppp" * 2 = "pppppp" › Both equal "pppppp" (6 p's) For beginners: Multiplication is commutative! 2*3 = 3*2 = 6. Same for strings: repeating "p" 6 times…
Alternative A Because of the concatenation of elements in dunders of syr class, the statement test if "pppppp" equals to "pppppp".
True a = ("p" * 2) * 3 and b = ("p" * 3 ) * 2 both will output pppppp, that is, six times p
It will be true if the value of p character is considered. Else it throws error
Answer: True In python when you multiply any string with any number it just creates that many number of same string inside that string only Example: “a” * 2 = “aa” Example: “ab” * 2 = “abab” Answer is true because 6 times p is equal to 6 times p
A: a = ("p" * 2) * 3 and b = ("p" * 3 ) * 2 both will output pppppp.
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