Python Question / Quiz; What is the output of the following Python code, and why? Comment your answers below!
Answer: C) True False Type comparison trap! › 5.0 is equal to 5, numbers compared by VALUE › '5' (string) isn't equal 5 (int) because of different types! For beginners: › int/float compare by value (5==5.0) › String vs number NEVER equal ('5' != 5)!
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The correct answer is C: True False. The first print statement checks if the floating-point number 5.0 is in list1. Python considers 5.0 to be equal to the integer 5, so this evaluates to True. The second print statement checks if the string '5' is in list1. The list .
✅ Answer: True False Alright, let’s level it up for the Python pros 🐍
True False. 5 is int and 5.0 is float. Both inherit from a common abstract base called numbers.Number, which defines equality across numeric types based on numeric value, not type. So 5 == 5.0 '5' is string so 5 in list1 returns False.
True False This here explains the equality of numbers So it checks if 5.0 == 5, which is mathematically correct But strings cannot equal numbers
5 False False As first print function outputs 5 as intger then validates 0 in list to False with a space instaed of new line Then second print outputs False as string '5' is not found in list
C. 5 returns True against query for 5.0 in list1. '5' is str type and list1 has no str type members
C) >>> print(5.0 in list(range(1,6))) True >>> print("5" in list(range(1,6))) False
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