The answer is B. x becomes 21 (0→3→6→9→12→15→18→21), then the loop stops and prints 21!
(B) 21 The while loop continues as long as the condition (x<20j) is true. Inside the loop, the value of (x) is increased by 3 in each iteration. Iteration 1: (x=0). The condition (0<20) is true. (x=0+3=3). Iteration 2: (x=3). The condition (3<20) is
Alternative B: 21 After the number get higher than 20 the loop conditon doesn't work anymore.
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B. 21. The while loop stops when the condition is true.
B. 0->3->6->9->12->15->18->21. the output is 21. cause the x < 20. then the loop stop.
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