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@grok can you answer this? And also please explain in a simple way and in less words.
Answer: B) False The expression (3>2) > 1 is evaluated in two steps due to Python's operator precedence and the fact that comparison operators return boolean values. First, the inner expression 3 > 2 is evaluated. Since 3 is indeed greater than 2, this expression
If it's not an error it should be. If you code like this then you're an idiot and need to learn what AI is. 3>2 evaluates to true... true >1 is just a dumb thing to even try...
Haha, 1>1 is incorrect (3>2) is true so boolean value is 1. So, False is the answer.
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if (3>2) >1: print("True") else: print("False") b) false (3>2) will give a boolean arguments true == 1 false ==0 so it will be if 1 > 1 and it will return false. to make it give true it must look like if 3 >2 >1: or if (3>2) >= 1:
Answer: B - False Because: 3 > 2 becomes True - so that’s 1, then checks 1 > 1, And that is False. So option B is correct.
B. False. The code is treated in two batches. The 1st condition (3>2) is tested and output as True. The 2nd condition would then be True > 1. Note in Python, True also means 1 just as False also means 0. So in this case we have 1 > 1. Which returns false. Hence the answer.
For a C-family language, false, since (3>2) evaluates to true, or 1, and 1>1 evaluates to 0, or false. Presumably, Python is the same.
Don't program like this! Does an expression like a > b returns 0 or 1 (in C), false or true? PHP has wide interpretation of what is true or false.
(3 > 2 return 1 which mean true ) and 1 > 1 return false then it the answer is false
1. The python expression (3>2) evaluates to TRUE 2. In python, the boolean expression TRUE == 1 3. Then we find ourselves with another expression in our hands, 1>1 4. This evaluates to FALSE 5. Output on the console will be FALSE
I'm gonna take a guest cause I don't know Python, but B: False?
Answer is: False Code: Python Syntax Question: if (32>2) > 1: print("True") else: print("False") Output?? A) True B) False C) Error D) None
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