synthv4's profile picture. what a terrible time to be homesick when you're not even sure what home is anymore

synthv

@synthv4

what a terrible time to be homesick when you're not even sure what home is anymore

这是doomposting 和 doomscrolling


damn... 真的想睡觉, but 我要死 bro i cant take this anymore


Actually doomscrolling rn everything is dire i hope that i dont start thinking about hopping into an early grave


Its ok... video game calm..


Lowkey so mad rn i want to crashout but ts aint even deserving of a crashout bruh its a goddamn tantrum


Lots of things bought.. can't wait to pass over so i dont have the evil presence in my bag... Wait for 9.9 to come for shirt...


nCr × p^r × q^(n - r) var = npr mean = np Mutually exclusive = 0 P(A∩B) = P(A) × P(B) P(AUB) = P(A) + P(B) - P(A∩B) P(A\B) = P(A∩B)/P(B) and vice versa 2 hour 5 questions are scary as shit


it would feel good P(A∩B) = P(A)× P(B) P(AUB) = P(A) +P(B) - P(A∩N) P(A∩B) when mutually exclusive = 0 P(A\B) = P(A∩B)/P(B)


X ~ b, N ~ p, N is fixed number of trials, P is probability of success r is the number of successes from the trials q is 1 - p P(X=x) = nCr × p^r × q^ n-r mean(E(x)) is np var is npr


P(A ∩ B) = P(A) × P(B) P(A U B) = P(A) + P(B) - P(A∩B) P(A\B) = P(A∩B)/P(B) Mutually Exclusive P(A∩B) = 0


bite my hand off geg jt off


nothing will be left of you Var(aX) = a^2 × var(X) Var(k) = 0 Var(X+Y) = Var(X) + Var(Y) Var(X - Y) = Var(X) + Var(Y) Var(aX+b) = Var(aX) + Var(b) = a^2×Var(X)+0 =a^2×Var(X) Var(aX-bY) = Var(aX) + Var(bY) = a^2×Var(X) +b^2× Var(Y)


you will not amount to anything E(aX) = aE(x) E(k) = k (constant) E(X+Y) = E(X) + E(Y) E(X - Y) = E(X) - E(Y) E(aX + b) = E(aX) + E(b) = aE(X)+b E(aX - bY) = E(aX) - E(bY) = aE(X) - bE(Y)


lowkey i think i need to die E(x) = sum of x P(X=x ) Var(x) = sigma squared which is the sum of (x)^2 - [E(x)]^2 Std dev = square root of sigma aka square root var x


i nneed that cookie so bad. so bad... my brain needs it i need it


Independent Events: P(A ∩ B) = P(A) × P(B) Mutually Exclusive P(A ∩ B) = 0 Conditional P(A\B) = P(A∩B)/P(B) The Union P(A U B) = P(A) + P(B) - P(A ∩ B)


nCr × p^r × q^(n -r), whereupon X = x is B ~ n = n, p and 1 - p = q while r = no. of successes from the fixed number of trials


i need someone to study s bro like shes cursing me to be an endeavour yume.... this yumeshipping thing be serious im out!!!!


synthv reposted

makan dgn @BrosDragons dan @synthv4 .. Nemi berseronok minum teh limau ais... jom kita makan dgn baik, ya.. 🥰🤍

vitrasolis's tweet image. makan dgn @BrosDragons dan @synthv4 ..  Nemi berseronok minum teh limau ais... jom kita makan dgn baik, ya.. 🥰🤍

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