workmath30's profile picture. I was born on point(3,0) in 1998 and I am currently attending new Manchester high school

Rational Fraction

@workmath30

I was born on point(3,0) in 1998 and I am currently attending new Manchester high school

I got a photo on stage with Demi Lovato! #episode #demipathtofame#im getting married#dreams bit.ly/EpisodeNow

workmath30's tweet image. I got a photo on stage with Demi Lovato! #episode #demipathtofame#im getting married#dreams  bit.ly/EpisodeNow

Domian is how far you go let tot right on a graph and stop where you stop if you have a Vertical Asymptote.


Range is how far you go up and down on a graph and where you stop if you have a Horizotal asymptote.


line bout does no touch it. x-intercept is when a line crosses through the x-axis and y-intercept is when a line crosses through the y-axis.


Holes happen when you re able to cross out something in the numerator and denominator. Aasymptote is a line hat gets very close to a another


7 M domain is all real number but 3 because my vertical asymptote is at 3


6. My range, is all real number because i don't have a horizontal asymptote


5a Because when you plug zero in to my original problem you get 0/24 which equals zero

workmath30's tweet image. 5a
Because when you plug zero in to my original problem you get 0/24 which equals zero
workmath30's tweet image. 5a
Because when you plug zero in to my original problem you get 0/24 which equals zero

5 my y-intercept which is something not to be proud of because it is a ftd( Factored Transmitted Disease) but i don't have one haha


4a. set my factored numerator to zero and found out that i have two of them one at 0 and the other at -4

workmath30's tweet image. 4a.
set my factored numerator to zero and found out that i have two of them one at 0 and the other at -4

4. The best thing to me that i have that most other rational fractions don't have is a Vertical Asymptote which i found when i


3. My Horizontal Asymptote was the easiest to find because my numerator had the biggest exponent which tells me that i have no H.A


2. I found my vertical Asymptote by setting the denominator of my factored self to zero and got x can not equal 3

workmath30's tweet image. 2.
I found my vertical Asymptote by setting the denominator of my factored self to zero and got x can not equal 3
workmath30's tweet image. 2.
I found my vertical Asymptote by setting the denominator of my factored self to zero and got x can not equal 3

1b i plugged -2 back into my factored part, solved and got my y value making the locationn of my hole at (-2,-4/5

workmath30's tweet image. 1b
i plugged -2 back into my factored part, solved and got my y value making the locationn of my hole at (-2,-4/5
workmath30's tweet image. 1b
i plugged -2 back into my factored part, solved and got my y value making the locationn of my hole at (-2,-4/5

1a by doing so i fond that x+2) cancels out and i set that to zero, solved and got -2 that was my x value for my hole

workmath30's tweet image. 1a
by doing so i fond that x+2) cancels out and i set that to zero, solved and got -2 that was my x value for my hole

1. Hi, my name is factor and did you know that my halo is at (-4/5, -2). Want to know how I found it, well i first factored myself out.


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