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UP Board Solutions for Class 8 Maths Chapter 4 सर्व समिकाएँ upboardguide.com/class-8-maths-… #UPBoardSolutions #Class8MathsChapter4


chamuyé tan bien en matemática q d un 4 pasé a un 8


x^2 + 8x + 16 = 0 ( x + 4 ) ( x + 4 ) = 0 x = -4


8!=(4x)(4!) 4x=(8×7×6×5×4!)/4! 4x=1680 x=420


<=>|x+8|=8 <=>x=-8±8 <=>S={0,-16}


(x + 8)^2 = 64 | sqrt x + 8 = +/- 8 | -8 x(1) = 0 x(2) = - 16


8 is answer √12/(√3/4) =(2√3*4)/√3 = 2*4=8


Wie bitte 5x8 ist 45 ??? 8 + 8 = 16 16 + 8 = 24 24 + 8 = 32 32 + 8 = 40


X ⁸ = 81 X = ± ⁸ √ 81 = ± ⁸ √( 3 ⁴ ) = ± 3 ( ⁴ / ⁸ ) = ± 3 ( ¹ / ² ) = ± √ 3 Ans.


x + 8 = 8 or -8 x = 8-8 or -8-8 x = 0 or -16


(X+8)(X+8)=64 X²+16X+64=64 X²+16X=64-64=0 X²=16X X =16


x + 8 = sqrt(64) x + 8 = 8 | x + 8 = -8 x = 0 | x = -16


(x+8)² = 64 x²+16x+64 = 64 x²+16x+64-64 = 0 x²+16x = 0 x(x+16)= 0 x= 0 or x= -16 x = 0, (0 + 8)² = 64 ✅ x = -16 = (-16 + 8)²= (-8)²= 64 ✅


x = 0 or x = -16 (x + 8)^2 = 8^2 |x + 8| = 8 thus x + 8 = 8 and x + 8 >=0 or -(x + 8) = 8 and x + 8 < 0 thus x = 0 and x >= -8 or x = -16 and x < -8 Both x = 0 and x = -16 satisfy both system of equations and inequalities.


x^8=3^4=((sqrt(3))^2)^4 x^8=(sqrt(3))^8 x=sqrt(3)


(x+8)^2= 64 => x+8=8 or -8=> x=0 or x=-16


(2/1/4 ) ^2; 2 x 4= 8; 8:1=8 8 x 8 = 64 =64


x + 8 = ±8 → x = –8 – 8 = –16 → x = 8 – 8 = 0 x = { –16 , 0 }


LMAO! An 8th grader who can easily follow algebraic logic, would be looking at her scratching their head, and then move on to solving the problem.


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