#hash_map search results
381Insert Delete GetRandom O(1) - Duplicates allowed - Hard #array #hash_map defaultdict(set) set.discard(v); set.pop()
460 LFU Cache - Hard #hash_map #OrderedDict .popitem(last=True) min_freq #LinkedHashMap idea 用 self.min_freq 记录最小频次, min_freq 总是从 1 加上去的. 每次加一. 不会跳跃.
I have solved First Unique Number In Stream, lintcode.com/problem/first-… idea: enumerate, #hash_map
I have solved Max Points on a Line, 100.00% lintcode.com/problem/max-po… idea: #hash_map, #math, duplicate y1 = y2, x1 == x2, infinite : x2 - x1 == 0,
We compared #stdmap vs #hash_map - see results: techwars.io/fight/stdmap/h…
I have solved Insert Delete GetRandom O(1), 93.24%, lintcode.com/problem/insert… init: el_idx[val] = array idx. idea: remove: swap current with tail, update el_idx[tail], pop tail. #hash_map, #array,
Maximum Size Subarray Sum Equals k, faster than 100.00%， lintcode.com/problem/maximu… #prefix_sum, #hash_map 前缀和之差等于K, sum_idx[prefix_sum] = i # 仅记录第一个相同值的前缀和的位置 当前位置找到一个 前缀和之差等于K的长度 比大小，返回大的 sum_idx = {0: -1} #Subarray,
solved Subarray Sum Equals K, faster than 100.00% lintcode.com/problem/subarr… idea: #hash_map, #prefix_sum, hashmap: sum_cnt = {} 记录 prefix_sum 出现的次数. sum_cnt[prefix_sum] += 1 if (prefix_sum - k) in sum_cnt: count += sum_cnt[prefix_sum - k] #Subarray init: sum_cnt = {0, 1}
460 LFU Cache - Hard #hash_map #OrderedDict .popitem(last=True) min_freq #LinkedHashMap idea 用 self.min_freq 记录最小频次, min_freq 总是从 1 加上去的. 每次加一. 不会跳跃.
381Insert Delete GetRandom O(1) - Duplicates allowed - Hard #array #hash_map defaultdict(set) set.discard(v); set.pop()
I have solved Max Points on a Line, 100.00% lintcode.com/problem/max-po… idea: #hash_map, #math, duplicate y1 = y2, x1 == x2, infinite : x2 - x1 == 0,
I have solved First Unique Number In Stream, lintcode.com/problem/first-… idea: enumerate, #hash_map
I have solved Insert Delete GetRandom O(1), 93.24%, lintcode.com/problem/insert… init: el_idx[val] = array idx. idea: remove: swap current with tail, update el_idx[tail], pop tail. #hash_map, #array,
Maximum Size Subarray Sum Equals k, faster than 100.00%， lintcode.com/problem/maximu… #prefix_sum, #hash_map 前缀和之差等于K, sum_idx[prefix_sum] = i # 仅记录第一个相同值的前缀和的位置 当前位置找到一个 前缀和之差等于K的长度 比大小，返回大的 sum_idx = {0: -1} #Subarray,
solved Subarray Sum Equals K, faster than 100.00% lintcode.com/problem/subarr… idea: #hash_map, #prefix_sum, hashmap: sum_cnt = {} 记录 prefix_sum 出现的次数. sum_cnt[prefix_sum] += 1 if (prefix_sum - k) in sum_cnt: count += sum_cnt[prefix_sum - k] #Subarray init: sum_cnt = {0, 1}
We compared #stdmap vs #hash_map - see results: techwars.io/fight/stdmap/h…
We compared #stdmap vs #hash_map - see results: techwars.io/fight/stdmap/h…
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