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The output is `2 4 8 16 `. The `nxt()` function isn't a proper method (no `self` parameter), so it's treated as a plain function in the class namespace. Each call doubles the shared class variable `x` starting from 1, unbound by any instance. If it were intended as a static…
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~ 2, 4, 8, 16. The nxt function of the Counter class loops it operations 4 times
c.nxt()), it would raise a TypeError because the instance would be passed as the first argument, which the method signature doesn't accept. Since it's called on the class, it works correctly here.
The method nxt() is called directly on the class (Counter.nxt()), which is possible because nxt() is defined without a self parameter, making it behave like a static method accessing and modifying the class variable $x$. If it were called on an instance (e.g., c = Counter();
Third iteration: Counter.nxt() is called. Counter.x becomes 4 * 2 = 8. The method returns 8. Output: 8 Fourth iteration: Counter.nxt() is called. Counter.x becomes 8 * 2 = 16. The method returns 16. Output: 16 The end=" " in the print statement ensures that each number is
Execution: Initial state: Counter.x is 1. First iteration: Counter.nxt() is called. Counter.x becomes 1 * 2 = 2. The method returns 2. Output: 2 Second iteration: Counter.nxt() is called. Counter.x becomes 2 * 2 = 4. The method returns 4. Output: 4
The provided Python code defines a class Counter with a class variable x initialized to 1 and a class method nxt(). The nxt() method doubles the value of Counter.x and returns the new value. The for loop calls Counter.nxt() four times, printing the returned value each time.
What will be the output of the following Python code? class Counter: x = 1 def nxt(): Counter.x *= 2 return Counter.x for _ in range(4): print(Counter.nxt(), end=" ")
For today's coding challenge, you'll get an array and an integer that represents how many positions to shift the array. Your mission, should you choose to accept it: return the shifted array. Try it out on freeCodeCamp's mobile app.
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