EquationSolved's profile picture. Just your typical math nerd that hardly ever gets on...

Equation Solved

@EquationSolved

Just your typical math nerd that hardly ever gets on...

Factors of c that sum to b is 3 and -2. Therefore, it factors into this: (x + 3) (x - 2)


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we put them into a calculator and get about 2/5 for the first. for the other, we end up getting about 3/2. Equation Solved.


then we simplify more, and get x= [-11 +- sqr root (242)] over 20. then we split it apart to two equations to fins the two answers.


we simplify that, and get x= [-11 +- sqr root (121 + 40*6)] over 20.


then we plug those into the formula. we would get x= [-11+- sqr root (11-4*10*-6)] over 2*10


now we use the quadratic formula. we find a, b, and c to do that. a would equal 10, b=11, c=-6.


now we put it into the form of y=. so y=10x² + 11x - 6


now we times everything by two to get rid of fractions. it should look like this: 10x² + 11x - 6 =0


we can see the parts of the equation are 3, -11/2x, and -5x², with 0 on the other side. we rearrange it to look like this: 5x²+11/2 x−3=0


solve for the x intercepts. (solution, zero, root, x-int) 3 − 11/2 x − 5x² = 0


which gets us 44. so there are 2 solutions. Equation Solved.


so 16 - -28, which is the same as 16 + 28.


here's what it will look like: -4 * -4 - 4 * 1 * -7


now we plug that into the discriminant; b*b - 4ac we need to keep in mind that if our answer is >0,2 solution; <0,no solution; =0,1 solution


now we can get what a, b, and c equal! comparing y=x*x-4x-7, and y=ax*x+bx+c, you can tell that 1 has the place of a, -4 as b, -7 as c.


for this equation you simply change 0 to y, and have them switch sides so it looks like this: y = x*x - 4x - 7


you need to find what a, b, and c equal. the quadratic equation is y=ax*x+bx+c, so lets put our equation into that formula.


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