LearnstemwithAI
@LearnwithAdutt
Ontario high school math, science, and CS made simple. Exploring engineering admissions with the help of AI. By A Dutt.
Basketball = impulse. Stop a 0.62 kg ball from 8 m/s in 0.20 s → F_avg ≈ (0.62×8)/0.20 ≈ 25 N. “Give” with the catch to raise Δt and lower force on your hands. #HCDSB #MCR3U #SportsScience #STEM #Math #Quadratics #Functions #Parabola #Baseball #BlueJays #Ontario #Canada…
Ice hockey bench chem: make 0.25 M NaCl, 300 mL. n=MV=0.25×0.300=0.075 mol → mass≈0.075×58.44≈4.38 g salt; dissolve and top to 300 mL. #HCDSB #MCR3U #SportsScience #STEM #Math #Quadratics #Functions #Parabola #Baseball #BlueJays #Ontario #Canada #HighSchool #StudyGram#HDSB…
Baseball launch: v=35 m/s at 35°. Range R=(v²/g)sin2θ ≈ (1225/9.8)×0.94 ≈ 117 m. Functions predict fence-clearing shots. #MCR3U #SportsScience #STEM #Math #Quadratics #Functions #Parabola #Baseball #BlueJays #Ontario #Canada #HighSchool #StudyGram#HDSB #PDSB #TDSB #YRDSB…
Baseball homerun = quadratic motion. y = −0.11x² + 0.88x + 1 ⇒ vertex at x=4 m → peak height ≈2.76 m. Parabolas make the long shot predictable! #MCR3U #SportsScience
Hockey gear cleanup = dilution in play! Need 250 mL of 0.40 M cleaner from 1.6 M stock? C1V1=C2V2 ⇒ V1=(0.40×250)/1.6=62.5 mL. Top up with water, chemistry assist! #SCH3U #STEM
Basketball rebound = momentum transfer. A 0.60 kg ball moving at 7 m/s reverses on impact → Δp = 8.4 N·s! Players absorb force by increasing contact time — that’s impulse in action. #SPH3U #SportsScience
Baseball arc = quadratic. Model y=−0.12x²+0.9x+1; vertex x=−b/(2a)=3.75 m ⇒ peak height ≈2.69 m. Functions predict the sweet spot! #MCR3U #SportsScience
Ice hockey bench chemistry: Need 200 mL of 0.25 M sanitizer from 2.0 M stock? C1V1=C2V2 ⇒ V1=(0.25×200)/2.0=25 mL. Add 175 mL water. #SCH3U #STEM
Basketball catch = impulse control: same momentum change over more time = less force. Ball 0.62 kg at 8 m/s ⇒ J≈5.0 N·s; with 0.20 s contact, F≈25 N. Cushioning matters! #SPH3U #SportsScience
Fly ball = parabola. Model: y = −0.12x² + 0.9x + 1. Vertex at x = −b/(2a) = 3.75 m; peak y ≈ 2.69 m. Functions predict launch height + when it happens. CTA: Guess the peak, then do the math! #MCR3U #Math #Functions #Quadratics #SportsScience #STEM #Ontario #Canada #Baseball…
Bench chem for clean visors! Make 0.25 M from 2.0 M stock, 200 mL total → C₁V₁=C₂V₂ ⇒ V₁=(0.25×200)/2.0=25 mL stock + 175 mL water. CTA: Save this for next lab (or the locker room). #SCH3U #Chemistry #STEM #Ontario #Canada #Hockey #Leafs #CdnSTEM #TDSB #YRDSB
Ever notice a smoother catch when you “give” with the ball? That’s impulse. Stop a 0.62 kg ball from 8 m/s. If Δt=0.05 s → F≈99 N. Stretch to 0.20 s → F≈25 N. Longer contact = less force on hands. CTA: Try a soft catch and tag your team! #SPH3U #Physics #SportsScience #STEM…
Baseball parabola: y = -0.12x² + 0.9x + 1 (x in m). Vertex at x = -b/(2a) = 3.75 m; peak y ≈ 2.69 m. Quadratics = launch arcs IRL. #MCR3U #SportsScience
Ice hockey bench chem: dilute 2.0 M isopropyl stock to clean visors at 0.25 M. C1V1=C2V2 → V1=(0.25×200 mL)/2.0=25 mL stock + 175 mL water. Safe & accurate dilution math! #SCH3U #STEM
Basketball physics: a chest pass with ~40 N over 0.5 m does W = F·d = 20 J on a 0.62 kg ball, giving v ≈ √(2W/m) ≈ √(40/0.62) ≈ 8.0 m/s. Energy → speed! #SPH3U #SportsScience @HCDSB
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