Code 4 Learning

@code4learning

Code Snippets 4 learning

India

انضم في أغسطس 2023

57المنشورات 859المتابعون 1ألفالمتابَعون

مثبتة

Code 4 Learning

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Binary Tree Inorder traversal without recursion

Code 4 Learning

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Cycle in Linked List

code4learning's tweet image. Cycle in Linked List

code4learning's tweet image. Cycle in Linked List

Code 4 Learning

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Validate Binary Search Tree using Inorder Traversal

code4learning's tweet image. Validate Binary Search Tree using Inorder Traversal

Code 4 Learning

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Validate Binary Search Tree

code4learning's tweet image. Validate Binary Search Tree

Code 4 Learning

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Binary Tree PostOrder traversal

code4learning's tweet image. Binary Tree PostOrder traversal

Code 4 Learning

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Invert Binary Tree

code4learning's tweet image. Invert Binary Tree

code4learning's tweet image. Invert Binary Tree

Code 4 Learning

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Minimum Depth of Binary Tree

code4learning's tweet image. Minimum Depth of Binary Tree

Code 4 Learning

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Recursion makes Binary tree problems a lot easier. The real challenge is doing without recursion

Code 4 Learning

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Maximum Depth of Binary Tree

code4learning's tweet image. Maximum Depth of Binary Tree

Code 4 Learning

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Count Nodes in Binary Tree

code4learning's tweet image. Count Nodes in Binary Tree

Code 4 Learning

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Symmetric Tree?

code4learning's tweet image. Symmetric Tree?

Code 4 Learning

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Binary Tree Level Order Traversal

code4learning's tweet image. Binary Tree Level Order Traversal

Code 4 Learning

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Binary tree inorder traversal

code4learning's tweet image. Binary tree inorder traversal

Code 4 Learning أعاد

Code 4 Learning

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Binary Tree Inorder traversal without recursion

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Code 4 Learning

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Square root of a number using binary search

code4learning's tweet image. Square root of a number using binary search

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Code 4 Learning

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LeetCode 191. Number of 1 Bits Input: n = 00000000000000000000000000001011 Output: 3 Using Java logical operator (>>>) : 10001 >>> 1 => 01000 Two Steps: 1) & with 1 2) Shift bit by one using >>>

code4learning's tweet image. LeetCode 191. Number of 1 Bits
Input: n = 00000000000000000000000000001011
Output: 3

Using Java logical operator (&gt;&gt;&gt;) :
10001 &gt;&gt;&gt; 1 =&gt; 01000

Two Steps:
1) &amp; with 1
2) Shift bit by one using &gt;&gt;&gt;

Code 4 Learning أعاد

Code 4 Learning

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Binary Search: Search in a sorted array in log(n) time.

code4learning's tweet image. Binary Search: Search in a sorted array in log(n) time.

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