Code 4 Learning

@code4learning

Code Snippets 4 learning

India

於八月 2023 加入

57貼文 852位跟隨者 1千個跟隨中

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Code 4 Learning

2023年9月28日

Binary Tree Inorder traversal without recursion

Code 4 Learning

2023年10月6日

Cycle in Linked List

code4learning's tweet image. Cycle in Linked List

code4learning's tweet image. Cycle in Linked List

Code 4 Learning

2023年10月5日

Validate Binary Search Tree using Inorder Traversal

code4learning's tweet image. Validate Binary Search Tree using Inorder Traversal

Code 4 Learning

2023年10月5日

Validate Binary Search Tree

code4learning's tweet image. Validate Binary Search Tree

Code 4 Learning

2023年10月4日

Binary Tree PostOrder traversal

code4learning's tweet image. Binary Tree PostOrder traversal

Code 4 Learning

2023年10月3日

Invert Binary Tree

code4learning's tweet image. Invert Binary Tree

code4learning's tweet image. Invert Binary Tree

Code 4 Learning

2023年10月2日

Minimum Depth of Binary Tree

code4learning's tweet image. Minimum Depth of Binary Tree

Code 4 Learning

2023年10月2日

Recursion makes Binary tree problems a lot easier. The real challenge is doing without recursion

Code 4 Learning

2023年10月2日

Maximum Depth of Binary Tree

code4learning's tweet image. Maximum Depth of Binary Tree

Code 4 Learning

2023年10月2日

Count Nodes in Binary Tree

code4learning's tweet image. Count Nodes in Binary Tree

Code 4 Learning

2023年10月1日

Symmetric Tree?

code4learning's tweet image. Symmetric Tree?

Code 4 Learning

2023年10月1日

Binary Tree Level Order Traversal

code4learning's tweet image. Binary Tree Level Order Traversal

Code 4 Learning

2023年9月29日

Binary tree inorder traversal

code4learning's tweet image. Binary tree inorder traversal

Code 4 Learning 已轉發

Code 4 Learning

2023年9月28日

Binary Tree Inorder traversal without recursion

Code 4 Learning 已轉發

Code 4 Learning

2023年9月22日

Square root of a number using binary search

code4learning's tweet image. Square root of a number using binary search

Code 4 Learning 已轉發

Code 4 Learning

2023年9月7日

LeetCode 191. Number of 1 Bits Input: n = 00000000000000000000000000001011 Output: 3 Using Java logical operator (>>>) : 10001 >>> 1 => 01000 Two Steps: 1) & with 1 2) Shift bit by one using >>>

code4learning's tweet image. LeetCode 191. Number of 1 Bits
Input: n = 00000000000000000000000000001011
Output: 3

Using Java logical operator (&gt;&gt;&gt;) :
10001 &gt;&gt;&gt; 1 =&gt; 01000

Two Steps:
1) &amp; with 1
2) Shift bit by one using &gt;&gt;&gt;

Code 4 Learning 已轉發

Code 4 Learning

2023年9月20日

Binary Search: Search in a sorted array in log(n) time.

code4learning's tweet image. Binary Search: Search in a sorted array in log(n) time.

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